docs: update readme
KieSun
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README.md
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README.md
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成功采纳后，如果你面试遇到其他问题，笔者可以提供免费解答服务。
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[线上网站查看过往原题](https://jsgodroad.com/questions)
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### 今日原题
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第九题：[修改嵌套层级很深对象的 key](https://github.com/KieSun/fucking-frontend/issues/14)
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[第十三题：有没有做过什么困难的项目？](https://github.com/KieSun/fucking-frontend/issues/18)：
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```js
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const a = {
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a_y: {
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a_z: {
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y_x: 6
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},
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b_c: 1
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}
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}
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// {
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// ay: {
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// az: {
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// yx: 6
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// },
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// bc: 1
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// }
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// }
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```
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今天来做一道其实算是很常见的泛技术问题：有没有做过什么困难的项目？
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第八题：[对一个很长的名字数组，做分片更新名字请求](https://github.com/KieSun/fucking-frontend/issues/13)
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```js
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/*
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* 对一个很长的名字数组，做分片更新名字请求：
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* 1. 分片里的更新是并行的，执行 changeName
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* 2. 各个分片间是串行的，执行 sleep
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* 这个函数接受三个参数，名字列表、分片数量，每次分片后的等待时间
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* 比如：
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* slicePostTask(['aa', 'bb', 'cc', 'dd', 'ee', 'ff', 'gg', 'hh'], 2, 2000)
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* // => ['aa', 'bb']
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* waiting 2s
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* // => ['cc', 'dd']
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* waiting 2s
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* // => ['ee', 'ff']
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* waiting 2s
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* // => ['gg', 'hh']
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*/
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const changeName = (name) => new Promise((resolve, reject) => {
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setTimeout(() => resolve(name), 1000)
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})
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const sleep = time => new Promise((resolve, reject) => {
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setTimeout(resolve, time)
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})
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const slicePostTask = async (names, chunkSize, time) => {
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// todo
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}
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```
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第七题：[数据排重](https://github.com/KieSun/fucking-frontend/issues/11)
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<details>
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```js
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const dedup = (data, getKey = () => {} ) => {
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// todo
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}
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let data = [
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{ id: 1, v: 1 },
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{ id: 2, v: 2 },
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{ id: 1, v: 2 },
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];
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// 以 id 作为排重 key，执行函数得到结果
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// data = [
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// { id: 1, v: 1 },
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// { id: 2, v: 2 },
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// ];
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let data1 = [
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{ id: 1, v: 1, id1: 1 },
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{ id: 2, v: 2, id1: 2 },
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{ id: 1, v: 2, id1: 1 },
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]
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// 以 id 和 id1 作为排重 key，执行函数得到结果
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// data1 = [
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// { id: 1, v: 1, id1: 1 },
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// { id: 2, v: 2, id1: 2 },
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// ];
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```
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</details>
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第六题：[实现一个 chunk 函数](https://github.com/KieSun/fucking-frontend/issues/8)
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<details>
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```js
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/**
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* @param input
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* @param size
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* @returns {Array}
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*/
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_.chunk(['a', 'b', 'c', 'd'], 2)
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// => [['a', 'b'], ['c', 'd']]
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_.chunk(['a', 'b', 'c', 'd'], 3)
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// => [['a', 'b', 'c'], ['d']]
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_.chunk(['a', 'b', 'c', 'd'], 5)
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// => [['a', 'b', 'c', 'd']]
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_.chunk(['a', 'b', 'c', 'd'], 0)
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// => []
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```
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</details>
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第五题：[Promise.all 错误处理](https://github.com/KieSun/fucking-frontend/issues/6)
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<details>
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异步请求通过 Promise.all 处理，怎么让其中失败的所有请求重试。
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```js
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Promise.all([A, B, C, D])
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// 4 个请求完成后发现 AD 请求失败了，如果让 AD 请求重试
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```
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[答案](./Answer/1%20~%2010/5.md)
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</details>
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第四题：[消息队列](https://github.com/KieSun/fucking-frontend/issues/5)
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<details>
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页面上有三个按钮，分别为 A、B、C，点击各个按钮都会发送异步请求且互不影响，每次请求回来的数据都为按钮的名字。
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请实现当用户依次点击 A、B、C、A、C、B 的时候，最终获取的数据为 ABCACB。
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[答案](./Answer/1%20~%2010/4.md)
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</details>
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第三题：[请按照用例实现代码](https://github.com/KieSun/fucking-frontend/issues/3)
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<details>
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```js
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// 请使用原生代码实现一个Events模块，可以实现自定义事件的订阅、触发、移除功能
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const fn1 = (... args)=>console.log('I want sleep1', ... args)
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const fn2 = (... args)=>console.log('I want sleep2', ... args)
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const event = new Events();
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event.on('sleep', fn1, 1, 2, 3);
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event.on('sleep', fn2, 1, 2, 3);
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event.fire('sleep', 4, 5, 6);
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// I want sleep1 1 2 3 4 5 6
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// I want sleep2 1 2 3 4 5 6
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event.off('sleep', fn1);
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event.once('sleep', () => console.log('I want sleep'));
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event.fire('sleep');
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// I want sleep2 1 2 3
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// I want sleep
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event.fire('sleep');
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// I want sleep2 1 2 3
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```
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[答案](./Answer/1%20~%2010/3.md)
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</details>
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第二题：[以下代码输出什么，为什么？](https://github.com/KieSun/fucking-frontend/issues/2)，这道题目是第一题的进阶版本，更有趣了。
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<details>
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```js
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try {
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let a = 0
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;(async function() {
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a += 1
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console.log('inner', a)
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throw new Error('123')
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// a()
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})()
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console.log('outer', a)
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} catch(e) {
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console.warn('Error', e)
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}
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```
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[答案](./Answer/1%20~%2010/2.md)
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</details>
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第一题：[以下代码输出什么，为什么？](https://github.com/KieSun/fucking-frontend/issues/1)
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<details>
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```js
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try {
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(async function() { a().b().c() })()
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} catch (e) {
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console.log(`执行出错：${e.message}`)
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}
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```
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[答案](./Answer/1%20~%2010/1.md)
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</details>
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对于这个问题大家会如何作答？
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## 前端十五万字面试资料
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